Positive SSL
1 如圖所示,試求此平行力系之合力距C點之距離為若干?
A 3m
B 4m
C 5m
D 6m

合力R=∑Fy

=30-20-40+80=50(N,↑)

∑MC=30×1+20×0+40×1-80×4+100

=30+40-320+100=150(N.m,逆時針)

∑MC=50.X=150

X=3(m)