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1 如圖所示之周轉輪系,若輪2轉速為6,旋臂轉速為-4,則輪5之轉速為
A 10
B -19.5
C 26
D -29.5

e2→5 = T2×T4T3×T5 = 100×12080×50 =3

e2→5 = N5-(-4)6-(-4)

N5=26 rpm 順時計