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1 如圖所示之周轉輪系,各齒輪齒數分別為TA=30、TB=20、TC=10、TD=90,若ND=0,而NA=20rpm(順時針),則旋臂之轉向及轉速為何?
A 5rpm,順時針
B 5rpm,逆時針
C 10rpm,順時針
D 10rpm,逆時針

ND-NmNA-Nm = TATD

0-Nm20-Nm = 3090

-3Nm = 20-Nm

Nm = -10 rpm = 10rpm 逆時針