先算 `r_π`
`400k*I_B+0.7+1k*I_E` = 10.7
`400k*I_B+100k*I_B` = 10
`500k*I_B` = 10
`I_B` = `10/(500k)`
`I_B` = 0.02 mA
`r_π` = `(25m)/(0.02m)`
=1250Ω
化成交流等效電路,如下圖
`R_i` = 400k//`r_π`
= 400k//1.25k ≒ 1.25kΩ