Positive SSL
    14.素養(4)
1 如圖所示,L1 = 6H,L2 = 12H,M = 2H,求Lab
A 14H
B 16H
C 18H
D 22H

通電時L1與L2產生的磁力線極性相同,因此為串聯互助

LT = L1+L2+2M = 6+12+2×2 = 22H