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    14.素養(4)
A 660.3A
B 588.4A
C 384.7A
D 76.7A

因為負載 B 端發生短路,電路變成如上圖, 假設2個節點一個電壓為V,另一個為接地。假設電壓 V 節點的電流全部皆流出

為 KCL 可知:

V - 1102+0.1 + V0.1 + V - (-110)0.1 = 0

V - 110 + 21V +21V +2310 = 0

43V = -2200

V = -51.16 V

I2 = -51.16 + 1100.1

= 588.4A

A 203∠-90°A
B 203∠ 90°A
C 20∠-90°A
D 20∠ 90°A

相電流 Iab = 240∠0°12∠60° = 20∠-60° A

相電流 Ica = 240∠120°12∠60° = 20∠60° A

線電流 IA = Iab - Ica = 203∠-90° A