Positive SSL
    14.素養(4)
A I = 10∠0°A
B Z =10 ∠45°Ω
C 電路呈電感性
D I 的相位超前 V

如上圖

Z1 = 10 - j10 = 102∠-45° Ω

Z2 = 10 + j10 = 102∠45° Ω

I1 = 100∠0° / 102∠-45° = 52∠45° A

I2 = 100∠0° / 102∠45° = 52∠-45° A

I=I1+ I2 = 52∠45° + 52∠-45° A = 10 ∠0° A

電壓與電流相位差0°,表示此電路為純電阻電路

Z = 100∠0° / 10∠0° = 10∠0° Ω