Positive SSL
    14.素養(4)
1 電感器的電感為0.2H,若通過電感器的電流為i(t)=50+25t+3t2 (A),則在 10秒時,電感器兩端之電壓值為
A 13V
B 15V
C 17V
D 19V

e = L ∆I∆t = L didt

e(t) = 0.2 × ddt(50+25t+3t2) = 0.2×(25+6t)

e(10)=0.2×(25+6×10) = 0.2×85 = 17V