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    14.素養(4)
1 某電動機輸入1kW功率,其中有200W的損失,則該電機的效率為
A 90%
B 88%
C 83%
D 80%

Po = Pi - Ploss

Po = 1000 - 200 = 800W

η=Po / Pi)

= 800 / 1000 = 80%