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    14.素養(4)
A 20V
B 19V
C 18V
D 17V

條件1:

I = 10/2 = 5A

E = 5R1 + 10 - - - (1)


條件2:

I = 16/8 = 2A

E = 2R1 + 16 - - - (2)


(2) - (1) ⟹ -3R1 + 6 = 0

R1 = 2 Ω 代入 (2)

E = 2 × 2 + 16 = 20 V


V2 = 20 × 182+18 = 18V


A -4V
B -2V
C 0V
D 2V

假設最下面節點接地 0V

Vb = 0 - 2 = -2V

Vc = -2 + 1 = -1V

Vd = -1 + 3 = 2V

Ve = 0 + 2 = 2V

Va = 2 - 2 = 0V