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    14.素養(4)
1 如圖所示之電路,若R1=6Ω、R2=4Ω及R3=4Ω,則電流I1及I2分別為何? 103 統測
A I1=6A,I2=9A
B I1=9A,I2=7.5A
C I1=12A,I2=6A
D I1=18A,I2=3A

先把 R2、R3並聯

4Ω//4Ω = 2Ω

I1 = 24 × 26+2 =6A

R2、R3都是 4Ω,電流相同

所以 I2 = (24 - 6) / 2 = 9A